A) \[16.36\]
B) \[28\]
C) \[78\]
D) \[108\]
Correct Answer: A
Solution :
Voltage gain \[A=\frac{\mu {{R}_{L}}}{{{R}_{P}}+{{R}_{L}}}\] \[\mu =20\] \[{{g}_{m}}=3\times {{10}^{-3}},\,{{R}_{L}}=3\times {{10}^{4}}\] \[{{R}_{P}}=\frac{\mu }{{{g}_{m}}}\] Substituting the values \[A=16.36\]
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