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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1996

  • question_answer
    Expressions for e.m.f- and current in A.C. circuit are \[E=200sin\text{ }314\text{ }t\]volt and \[I=100\,\sin \,\left( 314t+\frac{\pi }{3} \right)A,\] the power factor will be: 

    A)  \[1/2\]                                                

    B)         \[1/4\]                                

    C)         \[1\]                                    

    D)         \[-1\]

    Correct Answer: A

    Solution :

    \[E=200\,\sin \,314\,t\] \[I=100\,\,\sin \left( 314t+\frac{\pi }{3} \right)\] Phase difference \[\phi =\frac{\pi }{3}\] Power factor \[\cos \phi =\cos \frac{\pi }{3}=\frac{1}{2}\]


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