A) \[1.8\times {{10}^{-7}}%\]
B) \[1.8\times {{10}^{-9}}%\]
C) \[3.6\times {{10}^{-7}}%\]
D) \[3.6\times {{10}^{-9}}%\]
Correct Answer: A
Solution :
\[[{{H}^{+}}]=\alpha \times N\] \[{{10}^{-7}}=\alpha \times 55.5\] Molarity of water = normality \[=55.5\] \[\alpha =\frac{{{10}^{-7}}}{55.5}=1.8\times {{10}^{-9}}\] \[=1.8\times {{10}^{-9}}\times 100\] \[=1.8\times {{10}^{-7}}%\]
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