A) \[{{(C{{H}_{3}})}_{2}}C=C{{H}_{2}}-three\,\,C\] atom \[s{{p}^{2-}}\] hybrid
B) \[HC\equiv C-CH=C{{H}_{2}}\]all the four C atom \[s{{p}^{3}}\] hybrid
C) \[{{(C{{H}_{3}})}_{4}}\] all C atom \[s{{p}^{3}}\] hybrid
D) \[{{C}_{6}}{{H}_{6}}\](benzene) all C atoms \[s{{p}^{2}}\]hybrid
Correct Answer: A
Solution :
All carbon atom have \[s{{p}^{2}}\]-hybridisation in benzene. In \[{{(C{{H}_{3}})}_{4}}C\] all carbon atom have \[s{{p}^{3}}\]hybridisation.
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