A) \[\frac{1}{\lambda }=R\left( \frac{1}{{{n}_{1}}^{2}}-\frac{1}{{{n}_{2}}^{2}} \right)\]
B) \[\frac{1}{\lambda }=R\left( \frac{1}{{{n}_{2}}^{2}}-\frac{1}{{{n}_{1}}^{2}} \right)\]
C) \[\frac{1}{\lambda }=R{{\left( \frac{1}{{{n}_{1}}}-\frac{1}{{{n}_{2}}} \right)}^{2}}\]
D) \[\frac{1}{\lambda }=R{{\left( \frac{1}{{{n}_{2}}}-\frac{1}{{{n}_{1}}} \right)}^{2}}\]
Correct Answer: A
Solution :
The wavelength of all the spectral lines of H atom can be given by \[\frac{1}{\lambda }=R\left( \frac{1}{{{n}_{1}}^{2}}-\frac{1}{{{n}_{2}}^{2}} \right)\] this expression.
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