A) Loss of weight be more for A
B) Loss of weight will be more for B
C) Loss of weight will be equal for both
D) Ratio of weight will be 1 : 2
Correct Answer: A
Solution :
\[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\times \frac{{{A}_{2}}}{{{A}_{1}}},\,\,\,{{l}_{1}}={{l}_{2}}\] \[\therefore \] \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{A}_{2}}}{{{A}_{1}}}\] \[\frac{1}{2}=\frac{{{A}_{2}}}{{{A}_{1}}}\] \[\therefore \] \[\frac{{{A}_{1}}}{{{A}_{2}}}=\frac{2}{1}\] Area of first wire is more, then it will feel more loss in weight.
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