A) 1/9
B) 1/27
C) 1/6
D) 1/8
Correct Answer: D
Solution :
Remaining quantity \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{9/3}}\] \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{3}}=\frac{{{N}_{0}}}{8}\] \[\frac{1}{8}\] of initial amount
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