RAJASTHAN PMT Rajasthan - PMT Solved Paper-1997

  • question_answer
    Two long thin parallel wires are placed at a distance (r) from each other carrying equal current \[I\] in opposite direction. The magnitude of force per unit length which is exerted by each wire on the other is :

    A) \[\frac{{{\mu }_{0}}{{I}^{2}}}{r}\]                             

    B)        \[\frac{{{\mu }_{0}}{{I}^{2}}}{2\pi r}\]                    

    C) \[\frac{{{\mu }_{0}}I}{2\pi r}\]                   

    D)        \[\frac{{{\mu }_{0}}^{2}I}{2\pi {{r}^{2}}}\]

    Correct Answer: B

    Solution :

    Force per unit length \[F=\frac{{{\mu }_{0}}}{2\pi }\frac{{{I}^{2}}}{r}\]


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