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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1997

  • question_answer
    if \[h=6.6\times {{10}^{-34}}J-\sec ,\] then energy of quanta of frequency \[{{10}^{15}}Hz\] will be:

    A)  \[6.6\,\times {{10}^{-19}}J\]     

    B)                         \[6.6\,\times {{10}^{-12}}J\]      

    C)         \[6.6\,\times {{10}^{-14}}J\]       

    D)                         \[6.6\,\times {{10}^{-4}}J\]

    Correct Answer: A

    Solution :

    Energy of quanta \[E=hv\] \[=6.6\times {{10}^{-34}}\times {{10}^{15}}=6.6\times {{10}^{-19}}J\]


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