A) benzene
B) ethyl alcohol
C) nitrobenzene
D) ammonia
Correct Answer: B
Solution :
\[{{C}_{2}}{{H}_{5}}-N{{H}_{2}}+HN{{O}_{2}}\xrightarrow{NaN{{O}_{2}}/HCl}\] \[\underset{Ethyl\,alcohol}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,+{{N}_{2}}\uparrow +{{H}_{2}}O\]
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