question_answer

Methyl phenyl ether on reaction with \[HN{{O}_{3}}\] and \[{{H}_{2}}S{{O}_{4}}\] results:

A)  

B)                        and       

C)                         

D)                         

Correct Answer: B

Solution :

\[\underset{Methyl\,phenyl\,ether}{\mathop{{{C}_{6}}{{H}_{5}}-O-C{{H}_{3}}}}\,+HN{{O}_{3}}+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}\]