A) \[TiC{{l}_{4}}\]
B) \[CrC{{l}_{3}}\]
C) \[MnC{{l}_{2}}\]
D) \[SeC{{l}_{3}}\]
Correct Answer: A
Solution :
\[TiC{{l}_{4}}\]has impaired electron so that it is paramagnetic compound.
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