A) alkene
B) alkyne
C) alkane
D) all of these
Correct Answer: A
Solution :
\[\underset{Ethylene\,bromide}{\mathop{{{C}_{2}}{{H}_{4}}Br}}\,\xrightarrow{+Zn\,\,Heat}\underset{Alkene}{\mathop{{{C}_{2}}{{H}_{4}}}}\,\]
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