A) \[12\]
B) \[14\]
C) \[13\]
D) \[10\]
Correct Answer: A
Solution :
\[0.01\text{ }M\text{ }NaOH\] \[(O{{H}^{-}})={{10}^{-2}}\] \[pOH=2pH=14-pOH\] \[pH=14-2=12\]
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