A) chloroform
B) ethelene
C) ethene
D) carbon tetra chloride
Correct Answer: C
Solution :
\[\underset{Ethene}{\mathop{C{{H}_{2}}}}\,=C{{H}_{2}}+\underset{Violet\,sol.}{\mathop{{{I}_{2}}}}\,\xrightarrow{{}}\underset{\begin{smallmatrix} Ethelene\,iodide \\ (colourless) \end{smallmatrix}}{\mathop{\underset{I}{\mathop{\underset{|}{\mathop{C}}\,}}\,{{H}_{2}}-\underset{I}{\mathop{\underset{|}{\mathop{C}}\,}}\,{{H}_{2}}}}\,\]
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