RAJASTHAN PMT Rajasthan - PMT Solved Paper-1998

  • question_answer
    Surface tension of a soap is \[2\times {{10}^{-2}}N/m,\] then calculate the work done to make a bubble of radius 1 cm:

    A) \[\text{4}\text{ }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-6}}}\text{J}\]              

    B)         \[\text{8}\text{ }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-6}}}\text{J}\]

    C)  \[\text{12}\text{ }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-6}}}\text{J}\]           

    D)        \[\text{16}\text{ }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-6}}}\text{J}\]

    Correct Answer: D

    Solution :

    Work done \[W=T.\,\,2A\] \[=2\times {{10}^{-2}}.\,2(4\pi \,{{r}^{2}})\] \[=2\times {{10}^{-2}}\times 2\times 4\pi \times {{({{10}^{-2}})}^{2}}\] \[=16\pi \times {{10}^{-6}}J\]


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