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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1998

  • question_answer
    An acidic solution whose concentration is equal to \[0.1M\]and the degree of ionization is 1%. Then the dissociation constant of acid will be:

    A)  \[1.01\times {{10}^{5}}\]

    B)                         \[1.01\times {{10}^{-5}}\]

    C)                         \[1.01\times {{10}^{3}}\]

    D)                         \[1.01\times {{10}^{-3}}\]

    Correct Answer: D

    Solution :

    \[h=\alpha C,\alpha \]= quantity of ion C =concentration                 \[h=1\times \frac{0.1}{100}\]                 \[=0.1\times {{10}^{-2}}\]                 \[h=1\times {{10}^{-3}}\]


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