A) \[HOCl\]
B) \[COC{{l}_{2}}\]
C) \[C{{l}_{2}}\]
D) \[HCOCl\]
Correct Answer: B
Solution :
\[CHC{{l}_{3}}+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}\underset{(Unstable)}{\mathop{Cl-\underset{Cl}{\mathop{\underset{|}{\mathop{\overset{Cl}{\mathop{\overset{|}{\mathop{C}}\,}}\,}}\,}}\,-OH}}\,\]
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