A) \[C{{r}^{+}}\]
B) \[M{{n}^{+2}}\]
C) \[F{{e}^{+3}}\]
D) \[C{{O}^{+3}}\]
Correct Answer: A
Solution :
The value of magnetic momentum calculated by \[\mu =\sqrt{n(n+2)}\] Where n = number of unpaired electron. There are 5 unpaired electron \[F{{e}^{+3}},\] \[M{{n}^{+2}},\] \[C{{r}^{+1}}\] So, \[\mu =5.9\]Bohr magneton
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