A) 100%
B) 200%
C) 300%
D) 400%
Correct Answer: A
Solution :
Tune period\[{{T}_{1}}=2\pi \sqrt{\frac{l}{g}}\] If length is increased by 300% \[{{T}_{2}}=2\pi \sqrt{\frac{l+3l}{g}}\] \[{{T}_{2}}-2{{T}_{1}}\] % increase in time period \[\begin{align} & =\frac{{{T}_{2}}-{{T}_{1}}}{{{T}_{1}}}\times 100 \\ & =100% \\ \end{align}\]
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