question_answer

Equivalent capacity between A and B is:

A)  \[2\mu F\]                        

B)         \[3\mu F\]                        

C)  \[4\mu F\]        

D)         \[0.5\mu F\]

Correct Answer: D

Solution :

Equivalent capacity of \[1\mu F\] and \[1\mu F\] capacitor joined in parallel \[C'=1+1=2\mu F\] Now, this circuit can be represented as Now, the total capacity of circuit in series \[\frac{1}{C}=\frac{1}{2}+\frac{1}{1}+\frac{1}{2}\]  \[C=\frac{1}{2}=0.5\mu F\]