A) \[\frac{1}{2}m{{\omega }^{2}}{{x}^{2}}\]
B) zero
C) \[{{m}^{2}}\]
D) \[\frac{1}{2}{{m}^{2}}{{\omega }^{2}}{{x}^{2}}\]
Correct Answer: A
Solution :
Potential energy of a particle executing simple harmonic motion at a distance x from mean positions\[=\frac{1}{2}m{{\omega }^{2}}{{x}^{2}}\]
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