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RAJASTHAN PMT Rajasthan - PMT Solved Paper-1999

  • question_answer
    The amount of heat required to change \[1\,gm\,({{0}^{\text{o}}}C)\] of ice into water of \[{{100}^{o}}C,\] is:

    A)  716 cal                 

    B)         500 cal

    C)  180 cal                 

    D) 100 cal

    Correct Answer: C

    Solution :

    Heat required to convert \[0{}^\circ C\] of ice into water = mi (L = Latent heat) Now, heat required to rise the temperature of water from \[0{}^\circ C\] to \[100{}^\circ C\]. \[=ms\Delta t\] Where s = specific heat, \[=\Delta t\] temperature difference Total heat \[=mL+ms\,\Delta t\] \[\begin{align}   & =1\times 80+1\times 1\times (100-0) \\  & =180\,cal \\ \end{align}\]


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