A) - 16 cm
B) + 32 cm
C) + 16 cm
D) - 32 cm
Correct Answer: D
Solution :
When lens is dipped in liquid, then its focal length\[=fe\] \[\frac{{{f}_{l}}}{{{f}_{a}}}=\left( \frac{_{a}{{n}_{g}}-1}{_{l}ng} \right)\] \[\frac{1.4-1}{^{=}\left( \frac{1.4}{1.6}-1 \right)}=\frac{0.4\times 1.6}{0.2}=3.2\] \[\frac{{{f}_{l}}}{10}=3.2\Rightarrow {{f}_{l}}=-32\,cm\]
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