RAJASTHAN PMT Rajasthan - PMT Solved Paper-1999

  • question_answer
    According to law of equal distribution of energy the mean energy of a molecule per degree of freedom is:

    A)  \[\frac{1}{2}KT\]                             

    B)         \[KT\]  

    C)  \[\frac{3}{2}KT\]                             

    D)         \[\frac{5}{2}KT\]

    Correct Answer: A


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