RAJASTHAN PMT Rajasthan - PMT Solved Paper-1999

  • question_answer
    Two particles of same mass having kinetic energies 100 J and 400 J, then ratio of their momentum will be:

    A)  2 : 1                      

    B)         1 : 2 

    C)  4 : 1                      

    D)         1 : 4

    Correct Answer: B

    Solution :

    Momentum\[p\propto \sqrt{E}\] \[\frac{{{p}_{1}}}{{{P}_{2}}}=\frac{\sqrt{{{E}_{1}}}}{{{E}_{2}}}\] \[\therefore \]                  \[\sqrt{\frac{100}{400}}=\frac{10}{20}=1:2\]


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