A) \[C{{o}^{2+}}\]
B) \[N{{i}^{+2}}\]
C) \[F{{e}^{3+}}\]
D) \[C{{u}^{+}}\]
Correct Answer: D
Solution :
\[C{{o}^{2+}},\] \[N{{i}^{2+}},\] \[F{{e}^{3+}}\] have \[3,\] \[2\] and \[5\] unpaired electrons respectively while in \[C{{u}^{+}}\] there is no any unpaired electron. This is the reason \[C{{u}^{+}}\] is colorless ion.
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