A) velocity will be constant
B) acceleration will be constant
C) acceleration will be variable
D) none of these
Correct Answer: B
Solution :
\[\therefore \] \[\begin{align} & X\propto {{t}^{2}} \\ & X=k{{t}^{2}} \\ & \frac{dX}{dt}=2kt \\ & \frac{{{d}^{2}}X}{d{{t}^{2}}}=2k \\ \end{align}\] \[\therefore \]acceleration = constant
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