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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    A force of 10 N displaces an object by 1 m. If work done is 50 J, then direction of force makes an angle with direction of displacement:

    A) \[0{}^\circ \]                      

    B)        \[60{}^\circ \]  

    C) \[90{}^\circ \]                   

    D)        \[30{}^\circ \]

    Correct Answer: B

    Solution :

    Work done \[W=F.s\cos \theta \]                   \[\text{cos}\,\text{=}\frac{1}{2}-\cos \,{{60}^{{}^\circ }}\] \[5=10\times 1\cos \theta \] \[\therefore \]              \[\,\text{=60}{}^\circ \]


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