question_answer

   Three capacitors of \[2\mu F,\]\[3\mu F,\] and \[6\mu F,\]are joined in scries with n battery of 10 volt, then amount of charge in\[3\mu F,\] capacitor will be:

A)  \[5\mu C\]                        

B)         \[10\mu C\]

C)  \[11\mu C\]                      

D)         \[15\mu C\]

Correct Answer: B

Solution :

Total capacity \[\frac{1}{C}=\frac{1}{2}+\frac{1}{3}+\frac{1}{6},C=1\mu F\] Amount of charge on \[3\,\mu F\] capacitor                          \[q=CV\] \[=1\times 10=10\mu C\]