RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    A lift is ascending by acceleration g/3. What will be the time period of a simple pendulum, suspended from its cilling? If its time period in stationary life is T:

    A)  \[\frac{T}{2}\]                  

    B)         \[\frac{\sqrt{3T}}{2}\]

    C)  \[\frac{\sqrt{3T}}{4}\]                  

    D)         \[\frac{T}{4}\]

    Correct Answer: B

    Solution :

    Time period\[T\propto \frac{1}{\sqrt{g}}\] \[\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{\sqrt{g+g/3}}{g}\] \[{{T}_{2}}=\frac{\sqrt{3}}{2}{{T}_{1}}\]


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