A) \[litre\text{ }mol{{e}^{-1}}\]
B) \[mole\,\,litr{{e}^{-1}}\]
C) \[litre\text{ }mol{{e}^{-2}}\]
D) \[mol{{e}^{2}}\text{ }litr{{e}^{-2}}\]
Correct Answer: B
Solution :
For this reaction, \[{{K}_{c}}=\frac{{{[X]}^{4}}\,{{[Y]}^{6}}}{{{[A]}^{4}}\,{{[B]}^{5}}}\] So the unit of \[{{K}_{c}}={{\left[ \frac{mole}{litre} \right]}^{(4+6)-(4+5)}}\] \[=mole\,litr{{e}^{-1}}\]
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