RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    In the following sequence of reaction the end product is: \[HC\equiv CH\xrightarrow[{{H}_{2}}S{{O}_{4}}]{H{{g}^{2+}}}A\xrightarrow[{{H}_{2}}O]{C{{H}_{3}}MgX}B\xrightarrow{O}C\]

    A)  \[C{{H}_{3}}COC{{H}_{3}}\]

    B)  \[C{{H}_{3}}CHO\]

    C) \[{{C}_{2}}{{H}_{5}}OH\]

    D)  \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\]

    Correct Answer: A

    Solution :

    \[HC\equiv CH\xrightarrow[{{H}_{2}}S{{O}_{4}}]{H{{g}^{2+}}}\underset{(A)}{\mathop{C{{H}_{3}}CHO}}\,\xrightarrow[({{H}_{2}}O)]{C{{H}_{3}}MgX}\] \[C{{H}_{3}}-\underset{(B)}{\mathop{\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,H}}\,-C{{H}_{3}}\xrightarrow{[O]}\]                                 \[C{{H}_{3}}-\underset{Acetone}{\mathop{\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,}}\,-C{{H}_{3}}+{{H}_{2}}O\]


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