A) \[{{C}_{6}}{{H}_{6}}\]
B) \[C{{H}_{3}}-C=C-C{{H}_{3}}\]
C) \[C{{H}_{3}}CH=C{{H}_{2}}\]
D) \[CH=CH\]
Correct Answer: A
Solution :
\[{{C}_{6}}{{H}_{6}}+{{C}_{6}}{{H}_{5}}COCl\xrightarrow[Friedel\,Craft\,reaction]{Anhy\,AlC{{l}_{3}}}\] \[\underset{Acetophenon}{\mathop{{{C}_{6}}{{H}_{5}}CO{{C}_{6}}{{H}_{5}}}}\,+HCl\]
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