question_answer

\[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\xrightarrow[{{0}^{o}}-{{5}^{o}}C]{NaN{{O}_{2}}/HCl}{{C}_{6}}{{H}_{5}}{{\overset{+}{\mathop{N}}\,}_{2}}Cl\] \[\xrightarrow[CuS{{O}_{4}}]{KCN}A\] product A is:

A)  \[{{C}_{6}}{{H}_{5}}OH\]     

B)  \[{{C}_{6}}{{H}_{5}}HS{{O}_{3}}\]

C)  \[{{C}_{6}}{{H}_{5}}CN\]      

D)  \[{{C}_{6}}{{H}_{5}}Cl\]

Correct Answer: C

Solution :

\[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\xrightarrow[{{0}^{o}}-{{5}^{o}}C]{NaN{{O}_{2}}/HCl}{{C}_{6}}{{H}_{5}}\overset{+}{\mathop{{{N}_{2}}C{{l}^{-}}}}\,\]