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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    The oxidation number of \[Cr\] in \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] is:

    A)  \[+6\]                  

    B)         \[-6\]                   

    C)  \[+4\]                  

    D)         \[-4\]

    Correct Answer: A

    Solution :

    In \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] the oxidation number of \[Cr\] \[2+2x+(-2\times 7)=0\]                 \[2+2x-14=0\]                 \[2x-12=0\]                 \[x=6\]


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