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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2001

  • question_answer
    A sound source producing waves of frequency 300 Hz and wavelength 1 m. Observer is stationary, while source is going away with the velocity 30 m/s, then apparent frequency heard by the observer is:

    A)  270 Hz                 

    B)         273 Hz

    C)  383 Hz                 

    D)         300 Hz

    Correct Answer: B

    Solution :

    Apparent frequency\[n=n\left( \frac{\upsilon }{\upsilon +{{\upsilon }_{s}}} \right)\] \[\upsilon =\] velocity of sound, \[{{\upsilon }_{s}}=\]velocity of source \[\therefore n=300\left( \frac{332}{332+30} \right)=273Hz\]


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