A) \[3.125\times {{10}^{13}}\]
B) \[3.125\times {{10}^{14}}\]
C) \[3.125\times {{10}^{15}}\]
D) \[3.125\times {{10}^{16}}\]
Correct Answer: A
Solution :
Energy produced from 1 nucleus = 200 MeV \[\text{=200}\times \text{1}\text{.6}\times \text{1}{{\text{0}}^{-13}}\] \[=320\,\times {{10}^{-13}}J\] Required energy = 1 kW x 1 sec = 1000 J \[\therefore \]Number of nucleus\[\begin{align} & =\frac{1000}{320\times {{10}^{-13}}} \\ & =3.125\times {{10}^{13}} \\ \end{align}\]
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