RAJASTHAN PMT Rajasthan - PMT Solved Paper-2001

  • question_answer
    If temperature of a body increases by 10%, then increase in radiated energy of the R body is:

    A)  10%                      

    B)         40%

    C)  46%                      

    D)         1000%

    Correct Answer: C

    Solution :

    Radiated energy is directly proportional to the fourth power of temperature \[E\propto {{T}^{4}}\] \[\begin{align}   & \frac{{{E}_{1}}}{{{E}_{2}}}={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}} \\  & ={{\left( \frac{T}{T+\frac{T}{10}} \right)}^{4}}={{\left( \frac{10}{11} \right)}^{4}} \\  & \frac{{{E}_{1}}}{{{E}_{2}}}=\frac{10000}{14641} \\ \end{align}\] \[\therefore \]in crease \[\frac{{{E}_{2}}-{{E}_{1}}}{{{E}_{1}}}\times 100=46%\,\text{(app}\text{.)}\]


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