A) 4 m/s2
B) 40 m/s2
C) 200 m/s2
D) 400 m/s2
Correct Answer: B
Solution :
\[T=2\pi \sqrt{\frac{m}{k}}\] \[=2\pi \sqrt{\frac{1}{400}}=\frac{2\pi }{20}\] Frequency \[=\frac{20}{2\pi }\] \[\omega =2\pi n=2\pi \times \frac{20}{2\pi }=20\] Total energy\[\begin{align} & E=\frac{1}{2}m{{\omega }^{2}}{{a}^{2}} \\ & 2=\frac{1}{2}\times 1\times 400\times {{a}^{2}} \\ & a=\frac{1}{10}{{m}^{2}} \\ \end{align}\] Acceleration\[\begin{align} & ={{\omega }^{2}}a-400\times \frac{1}{10} \\ & =40m/{{s}^{2}} \\ \end{align}\]
You need to login to perform this action.
You will be redirected in
3 sec
