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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2001

  • question_answer
    When a cell is balanced on potentiometer wire, then balancing length is 125 cm. If resistance of 2 ohm is connected across the ends of cell, then balancing length is 100 cm, then internal resistance of cell is:

    A)  \[0.5\,\Omega \]                            

    B)         \[0.25\,\Omega \]

    C)  \[0.05\,\Omega \]         

    D)         \[5\,\Omega \]

    Correct Answer: A

    Solution :

    According to formula of potentiometer \[r=\frac{{{l}_{1}}-{{l}_{2}}}{{{l}_{2}}}\times R=\frac{125-100}{100}\times 2=0.5\,\Omega \]


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