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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2001

  • question_answer
    This electronic configuration shows element of: \[\underset{1S}{\mathop{}}\,\,\,\,\,\,\,\,\,\,\,\underset{2S}{\mathop{}}\,\,\,\,\,\,\,\,\,\,\,\,\,\underset{2P}{\mathop{}}\,\]

    A)  oxygen                               

    B)  neon

    C)  fluorine              

    D)         nitrogen

    Correct Answer: C

    Solution :

    This electronic configuration shows atomic number 9. So that element is fluorine.


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