A) \[Si\]
B) \[Pa\]
C) \[P\]
D) \[Ra\]
Correct Answer: A
Solution :
\[_{12}M{{g}^{23}}{{\xrightarrow{+\alpha \,molecule}}_{14}}S{{i}^{27}}{{+}_{0}}{{n}^{1}}\]
You need to login to perform this action.
You will be redirected in
3 sec
