A) \[Br-C{{H}_{2}}-\overset{Br}{\mathop{\overset{|}{\mathop{C}}\,}}\,H-CH-C{{H}_{3}}\]
B) \[Br-C{{H}_{2}}-C{{H}_{2}}\overset{Br}{\mathop{\overset{|}{\mathop{-C}}\,}}\,H-C{{H}_{3}}\]
C) \[B{{r}_{2}}-C{{H}_{2}}-C{{H}_{2}}-\underset{Br}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{3}}\]
D) \[Br-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-\underset{Br}{\mathop{\underset{|}{\mathop{C}}\,}}\,{{H}_{2}}\]
Correct Answer: B
Solution :
\[\underset{1-\text{butane}}{\mathop{C{{H}_{2}}=CH-C{{H}_{2}}}}\,-C{{H}_{3}}+B{{r}_{2}}\xrightarrow{{}}\] \[Br-C{{H}_{2}}-C{{H}_{2}}-\underset{Br}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{3}}\]
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