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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2002

  • question_answer
    During an adiabatic expansion of 2 mole of gas, the change in internal energy was, found - 50 J. The work done during the process:

    A)  50 J                       

    B)         -50 J

    C)  100 J                    

    D)         0

    Correct Answer: A

    Solution :

    From 1st law of thermodynamics \[dQ=dU+dW\] From adiabatic process\[dQ=0\] \[\therefore \]  \[dW=-dU=-(-50)\]                                         \[=50\,\text{J}\]


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