RAJASTHAN PMT Rajasthan - PMT Solved Paper-2002

  • question_answer
    0.7 H inductance is connected with 220\[\Omega \]resistance with A.C. source it is connected to 50 Hz frequency and 220 volt e.m.f. source, then the value of current in circuit will be:

    A)  0.5 A                    

    B)         0.7A

    C)  5 A                        

    D)         7A

    Correct Answer: B

    Solution :

    Impedence of circuit \[Z=\sqrt{{{R}^{2}}+{{\omega }^{2}}{{L}^{2}}}\] \[\begin{align}   & =\sqrt{{{(220)}^{2}}+{{(2\pi \times 50)}^{2}}\times {{(0.7)}^{2}}} \\  & 220\sqrt{2} \\ \end{align}\] \[i=\frac{E}{Z}=\frac{220}{220\sqrt{2}}-\frac{1}{\sqrt{2}}=0.7\,\text{amp}\]


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