A) 0 1 mm
B) 0.5 mm
C) 1 mm
D) 2 mm
Correct Answer: C
Solution :
From \[T=\frac{rhdg}{2}\] Radius\[T=\frac{2T}{hdg}\] \[\begin{align} & =\frac{2\times 75\times {{10}^{-3}}}{3\times {{10}^{-2}}\times {{10}^{3}}\times }=50\times {{10}^{-5}} \\ & =0.5\times {{10}^{-3}}\,m=0.5\,mm \\ \end{align}\] Diameter = 2r \[=2\times 0.5\,=1\,mm\]
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