RAJASTHAN PMT Rajasthan - PMT Solved Paper-2002

  • question_answer
    V= 100 sin 100t,  \[I=100\] sin \[(100t+\pi /6\] then find the watt less power:

    A)  \[{{10}^{4}}\,W\]                                           

    B)  \[{{10}^{3}}\,W\]

    C)  \[{{10}^{2}}\,W\]           

    D)         \[4330\,W\]

    Correct Answer: D

    Solution :

         \[V=100\sin \omega t\] \[I=100\sin (100t+\pi /6)\] Comparing these equations with                                 \[V={{V}_{0}}=\sin \omega t\] and       \[{{I}_{0}}=100,{{V}_{0}}=100,\phi =\frac{\pi }{6}\] Power loss\[\begin{align}   & =\frac{100\times 100}{2}\times \frac{\sqrt{3}}{2} \\  & =4330 \\ \end{align}\]


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