A) \[\frac{{{\mu }_{0}}I}{2R}\]interior
B) \[\frac{{{\mu }_{0}}I}{2R}\]exterior
C) \[\frac{{{\mu }_{0}}I}{2R}\left( 1-\frac{1}{\pi } \right)\]
D) \[\frac{{{\mu }_{0}}I}{2R}\left( 1+\frac{1}{\pi } \right)\]exterior
Correct Answer: A
Solution :
Magnetic field at the centre of circular loop \[B=\frac{{{\mu }_{0}}l}{2R}\] interior.
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