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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2002

  • question_answer
    An open organ pipe of length 33 cm, vibratos with frequency 1000 Hz. If velocity of sound in 330 m/s. Then its frequency is:

    A)  fundamental frequency

    B)  first overtone of pipe

    C)  second overtone

    D)  fourth overtone

    Correct Answer: B

    Solution :

    Fundamental frequency \[{{n}_{1}}=\frac{\upsilon }{2l}\] \[=\frac{330}{2\times 33\times {{10}^{-2}}}=500Hz\] Frequency of 1st overtone \[=2\frac{\upsilon }{2l}=2\times 500=1000Hz\]


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